qdii qdii - 1 year ago 62
C++ Question

Can a cast operator be explicit?

When it comes to constructors, adding the keyword

prevents an enthusiastic compiler from creating an object when it was not the programmer’s first intention. Is such mechanism available for casting operators too?

struct Foo
operator std::string() const;

Here, for instance, I would like to be able to cast
into a
, but I don’t want such cast to happen implicitly.

Answer Source

Yes and No.

It depends on which version of C++, you're using.

  • C++98 and C++03 do not support explicit type conversion operators
  • But C++11 does.


struct A
    //implicit conversion to int
    operator int() { return 100; }

    //explicit conversion to std::string
    explicit operator std::string() { return "explicit"; } 

int main() 
   A a;
   int i = a;  //ok - implicit conversion 
   std::string s = a; //error - requires explicit conversion 

Compile it with g++ -std=c++0x, you will get this error:

prog.cpp:13:20: error: conversion from 'A' to non-scalar type 'std::string' requested

Online demo : http://ideone.com/DJut1

But as soon as you write:

std::string s = static_cast<std::string>(a); //ok - explicit conversion 

The error goes away : http://ideone.com/LhuFd

BTW, in C++11, the explicit conversion operator is referred to as "contextual conversion operator" if it converts to boolean.

BTW, if you want to know more about implicit and explicit conversions there is a good StackOverflow question about it here.

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