jsh114 jsh114 - 1 year ago 62
Java Question

Networking in Java, 'readLine()' on multiple lines of response in client

I'm currently writing a mail client that simply opens a connection to a mail server and receives the responses from it.

However, when I receive the response from the server, it only works when the response is one line. When the response is more than one line(multiple lines), then it only receives the first line of response.

If I could know the format of response such as there is \n at the end of each line, it would be easier to format the response. But since I'm only writing a client not the server, I don't know the response format as well.

Below is the code I have written.

public class Main {
private static Socket client;
private static final BufferedReader br
= new BufferedReader(new InputStreamReader(System.in));

public static void main(String[] args) {
try {
/* Input format checking before opening a connection,
the input must be a form of mail_server and port_number */
if (args.length != 2)

/* Set up the connection to mail server from the command line */
client = new Socket(args[0], Integer.parseInt(args[1]));

/* Initialize sender that sends message to the server */
PrintStream sender = new PrintStream(client.getOutputStream());

/* Initialize receiver that receives message from the server */
BufferedReader receiver
= new BufferedReader(
new InputStreamReader(client.getInputStream()));

while (true) {
/* Flushing buffer */
String message;

/* Printing the resulting response from the server */
while ((message = receiver.readLine()) != null) {

/* Get input message from the user */
message = br.readLine();

/* If the user inputs "exit", then the program terminates */
if (message.equals("exit")) System.exit(1);

/* If not exit, send the message to server */
} catch (Exception e) {
} finally {
try {
} catch (Exception e) {


I have also tried,

// Assuming that the output format has '\n' at the end of each lines
String[] messages = receiver.readLine().split("\n");

But it only prints out the first line of the response as well.

I have seen very similar question at Java server-client readLine() method but the question has been resolved by editing the server code where I can only change the client code.

Can anyone please suggests me any ideas?

Thanks in advance.

Answer Source

Hm i got it to work with netcat, e.g.:

nc -l -p 31337

After starting netcat you can type in some input which will be sent to the client after connecting.

So with netcat it works. I would recommend to use variables just for one purpose.

        /* Flushing buffer */
        String SvMessage;
        while (!receiver.ready()){} //wait for buffer
        /* Printing the resulting response from the server */
        while (receiver.ready()){
            SvMessage = receiver.readLine();

        /* Get input message from the user */
        String userMessage = "hello";

        /* If the user inputs "exit", then the program terminates */
        if (userMessage.equals("exit")) System.exit(1);

        /* If not exit, send the message to server */
        sender.print(userMessage + "\r\n");

I made some changes: 1.) changed while condition to br.ready() 2.) instead of PrintStream.println using PrintStream.print(message + "\r\n) 3.) not using a BufferedReader for userinput, just sending "commands" (or hello) 4.) added while (!receiver.ready()){} to wait for buffer to fill

So the client will now always reply to the server with new commands (or "hello"). =)

Hope this helps

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