Richard Stanton-Reid Richard Stanton-Reid - 1 year ago 137
AngularJS Question

File Upload Using AngularJS with php server script

I have reviewed the questions and answers on this topic and I dont think they fully answer my issues which are:

  • the upload using the angular frontend (whichever way this is handled) sends the file data to a script on the server such as a php script (which is my preferred method). Once the php script has run I want to return to the page from which the upload was made and give a message there..I dont want the php page to display. Will appreciate some guidance on how to achieve this. Ideally what code to add to the php script.

  • I want to capture and save to a database info relating to the file such as its name and data entered/selected by the user such as a document category. Is there a way to achieve this as part of the file upload? ie ideally the user will complete entries in a form which includes a file upload button so that the user selects the file to upload but only on the form submit being clicked is the file upload actioned along with the other form data being returned for processing.

I have spent 3 days on this.. so any help will be great.

Answer Source

You can use FormData objects to send form data to your server.It will allow you to send both files and text data at the same time. You can find more information about it here.


<body ng-controller="myCtrl">
    <div class="file-upload">
        <input type="text" ng-model="name">
        <input type="file" file-model="myFile"/>
        <button ng-click="uploadFile()">upload me</button>

In app.js, we create a custom directive fileModel, in which we listen for changes to the content of the input element and change the value of the variable in the scope accordingly. This is achieved using the $parse service to set the value in our scope.


var myApp = angular.module('myApp', []);

myApp.directive('fileModel', ['$parse', function ($parse) {
    return {
    restrict: 'A',
    link: function(scope, element, attrs) {
        var model = $parse(attrs.fileModel);
        var modelSetter = model.assign;

        element.bind('change', function(){
                modelSetter(scope, element[0].files[0]);

// We can write our own fileUpload service to reuse it in the controller
myApp.service('fileUpload', ['$http', function ($http) {
    this.uploadFileToUrl = function(file, uploadUrl, name){
         var fd = new FormData();
         fd.append('file', file);
         fd.append('name', name);
         $, fd, {
             transformRequest: angular.identity,
             headers: {'Content-Type': undefined,'Process-Data': false}

 myApp.controller('myCtrl', ['$scope', 'fileUpload', function($scope, fileUpload){

   $scope.uploadFile = function(){
        var file = $scope.myFile;
        console.log('file is ' );

        var uploadUrl = "save_form.php";
        var text = $;
        fileUpload.uploadFileToUrl(file, uploadUrl, text);




     $target_dir = "./upload/";
     $name = $_POST['name'];
     $target_file = $target_dir . basename($_FILES["file"]["name"]);

     move_uploaded_file($_FILES["file"]["tmp_name"], $target_file);

     //write code for saving to database 
     include_once "config.php";

     // Create connection
     $conn = new mysqli($servername, $username, $password, $dbname);
     // Check connection
     if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);

     $sql = "INSERT INTO MyData (name,filename) VALUES ('".$name."','".basename($_FILES["file"]["name"])."')";

     if ($conn->query($sql) === TRUE) {
         echo json_encode($_FILES["file"]); // new file uploaded
     } else {
        echo "Error: " . $sql . "<br>" . $conn->error;



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