sagar patel - 4 months ago 38

Javascript Question

**(i) When I run below code,**

`var fib = [];`

for(var i=1; i<=10; i++){

if (i === 1) {

fib[0] = 0;

} else if (i == 2) {

fib[1] = 1;

} else {

fib[i] = fib[i-2] + fib[i-3];

console.log(fib[i]);

}

}

Output: 0 1 undefined 1 NaN NaN

`function generateFib(num) {`

var fib = [];

for(var i=1; i <= num; i++) {

if (i === 1) {

fib.push(0);

} else if (i == 2) {

fib.push(1);

} else {

fib.push(fib[i - 2] + fib[i - 3]);

}

}

return fib;

}

generateFib(10);

Output: 0 1 1 2 3 5

I am confused between two code could you please explain me, thank you.

Answer

Follow the loops iterations one by one

in the third iteration,

`fib[2] = fib[2-2] + fib[2-3];`

is `fib[2] = fib[0] + fib[-1];`

`fib[2] = 0 + undefined;`

`fib[2] = undefined;`

in the fourth iteration,

`fib[3] = fib[3-2] + fib[3-3];`

is `fib[3] = fib[1] + fib[0];`

`fib[3] = 1 + 0;`

in the fifth iteration,

`fib[4] = fib[4-2] + fib[4-3];`

is `fib[4] = fib[2] + fib[1];`

`fib[4] = undefined + 1;`

`fib[4] = NaN;`

You can figure out the rest.

Btw you could use a debugger with breakpoints.

It would be really useful in this situation.