johnsnow85 johnsnow85 - 3 months ago 24
Java Question

Percentage using Random

Today I created a function which generates a

random
number (0, 1, 2 or 3).

But I want yo have a percetage function.

I would like to apply a percentage to every chance to which the generated numbers fall.

Example: 0 will have 60% chance of being drawn, the number 1 19%, ...

public void GenerGame(){

Random r = new Random();
int game = r.nextInt(max - min +1);

if (game == 0){
// do something
}
else if (game == 1){
// do something
}
else if (game == 2){
// do something
}
else {
// do something
}
}


Can I do it by using
Random
?

Answer

You can definitely do this by re-thinking your RNG.

If you change the random generation range to 0-99, you can think of this as a range of percentages produced, and hence prescribe various behaviors in those ranges.

public void GenerGame(){

    Random r = new Random();
    int game = r.nextInt(100);

    if (game < 60){ // 60%
        // do something
    }
    else if (game < 79){ // 19%
        // do something
    }
    else if (game < 93){ // 14%
        // do something
    }
    else { // 7%
        // do something
    }
} 

You could change the precision to tenths of a percent by boosting the range to 0-999.