Krzysiek - 5 days ago 4x

C++ Question

Is there a way to split a number and store digits in an int array?

I am looking for a way to remove some digits from a number (for a divisible algorithm proof).

for example, if I have a number 12345, I need to perform this operation:

1234 - 5 = 1229

Is there a way to do this?

Answer

Use `n % 10`

to get the last digit and `n / 10`

to get the others. For example, 5=12345%10, 1234=12345/10.

```
int array[6];
int n = 123456;
for (int i = 5; i >= 0; i--) {
array[i] = n % 10;
n /= 10;
}
```

In general, `vector`

s are preferred in C++, especially in this case since you probably don't know in advance the number of digits.

```
int n = 123456;
vector<int> v;
for(; n; n/=10)
v.push_back( n%10 );
```

Then `v`

contains `{6,5,4,3,2,1}`

. You may optionally use `std::reverse`

to reverse it.

Source (Stackoverflow)

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