Barry - 3 months ago 17

C++ Question

Consider the following:

`struct X {`

template <class T> operator T(); // #1

template <class T> operator T&(); // #2

};

int a = X{}; // error: ambiguous

int& b = X{}; // calls #2

int const& c = X{}; // calls #2

The situation for

`b`

`#2`

`#2`

`#1`

`int const&`

`int`

Answer

When deciding how to initialize a reference given its initializer, first, direct binding is tried. [dcl.init.ref]/(5.1.2):

If the reference is an lvalue reference and the initializer expression […] has a class type (i.e.,

`T2`

is a class type), where`T1`

is not reference-related to`T2`

, and can be converted to an lvalue of type “cv3`T3`

”, where “cv1`T1`

” is reference-compatible with “cv3`T3`

” (this conversion is selected by enumerating the applicable conversion functions (13.3.1.6) and choosing the best one through overload resolution (13.3)), then the reference is bound […] to the lvalue result of the conversion […].

The wording that governs the candidate selection for this process (13.3.1.6, as mentioned above) excludes the first conversion function:

The conversion functions of

`S`

and its base classes are considered.Those non-explicit conversion functions that are not hidden within(when initializing an lvalue reference or an rvalue reference to function) […], where “`S`

and yield type “lvalue reference tocv2`T2`

”cv1`T`

” is reference-compatible (8.6.3) with “cv2`T2`

”,are candidate functions. For direct-initialization, […].

Clearly, this exclusion is specific to the reference initialization semantics, so the first case is ambiguous still.