RedRose23 - 5 months ago 23

Python Question

I'm stuck in a very stupid point while reading Numeric Analysis.

So I have the following program in python. And I can't figure why I get these results.

Where do I use the

`i`

`heron(x,y)`

Because only the first one makes sense for me. Why are the numbers decreasing if the i isn't used at all at the function?

`def heron(x,y):`

x=(x+y/x)*0.5

return x

x=1

y=2

for i in range(5):

x=heron(x,y)

print('Approximation of square root : %.16f'%x)

And the results:

`Approximation of square root :1.5000000000000000`

Approximation of square root :1.4166666666666665

Approximation of square root :1.4142156862745097

Approximation of square root :1.4142135623746899

Approximation of square root :1.4142135623730949

Edit: The code was given by my professor in class and I guess the only use of it was to explain few basic things of Python?

Answer

The line

```
for i in range(5):
```

only means:

Do the following five times.

The actual work is done in

```
x = heron(x,y)
```

which uses `x`

as part of the arguments of `heron`

and assigns the changed value back to it. So while `y`

stays unchanged, `x`

is changed with each call to `heron`

. The changed `x`

is then used as an argument to the next call.

**Edit:** I can't decide if this is a correct implementation because I don't know what algorithm you are trying to implement. But you only asked:

Why are the numbers decreasing if the i isn't used at all at the function?