JSON Question
REST API on Python for JSON type data
I am currently trying to understand how to create a REST API using Python (Flask) which will allow user to GET a set of data represented in JSON format by browsing the url given as : localhost:5000/DPM. I wrote the following Python script but receive errors as such:
File "sqllite.py", line 23, in
api.add_resource(DPM, '/DPM')
File "C:\Program Files\Anaconda3\lib\site-packages\flask_restful__init__.py", line 404, in add_resource
self._register_view(self.app, resource, *urls, **kwargs)
File "C:\Program Files\Anaconda3\lib\site-packages\flask_restful__init__.py", line 444, in _register_view
resource_func = self.output(resource.as_view(endpoint, *resource_class_args,
AttributeError: type object 'DPM' has no attribute 'as_view'
from flask import Flask
from flask_restful import Resource, Api
from sqlalchemy import create_engine
import json
app = Flask(__name__)
api = Api(app)
class DPM:
def __init__(self, time, month):
self.time = time
self.month = month
ees = DPM('[12.18]','11')
def jdefault(o):
return o.__dict__
print(json.dumps(ees, default=jdefault, indent=4))
api.add_resource(DPM, '/DPM')
if __name__ == '__main__':
app.run(debug=True)
Where did I do wrong here?
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Answer Source
The class that you want to expose to your API must inherit from Resource, this class implements basic methods such as the as_view that allows you to render the output. and then you have to implement some method like for example the GET:
from flask import Flask
from flask_restful import Resource, Api
app = Flask(__name__)
api = Api(app)
class DPM(Resource):
def __init__(self):
self.time = '[12.18]'
self.month = "11"
def get(self):
return self.__dict__
api.add_resource(DPM, '/DPM')
if __name__ == '__main__':
app.run(debug=True)
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