sffc sffc - 1 year ago 100
C Question

Can you allow one of a few types of pointers as an argument without void*?

In plain , I have a situation where I would like to allow a function to accept multiple types of pointers. To illustrate my situation, here could be one use case:

void myfunction([int* or char*] value) {
*value = 0xdd; // safe since value is at least as big as a char*

And here is another:

#define MAGIC 0xabcdef0
typedef struct {
int magic;
char* content;
} MyStruct;

void myfunction([int* or MyStruct*] value) {
if (*value != MAGIC) {
printf("Got an int\n");
} else {
printf("Got a MyStruct\n");

// example:
int input1 = 0;
MyStruct input2 = { MAGIC, "hello world" };
myfunction(input1); // "Got an int"
myfunction(input2); // "Got a MyStruct"

Both of these situations could be made possible with a
parameter type, but that would in effect allow any type of pointer to be passed in without a compile error. Is there a way to restrict the function to accept only a specific subset of pointer types?

R.. R..
Answer Source

If you can use features that are new in C11, the _Generic keyword can solve your problem:

void myfunction(void *value) {
    // ...
#define myfunction(x) myfunction( \
    _Generic((x), char *: (x), int *: (x)) )
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