Pentium10 Pentium10 - 1 year ago 73
Java Question

Why I get UnsupportedOperationException when trying to remove from the List?

I have this code:

public static String SelectRandomFromTemplate(String template,int count) {
String[] split = template.split("|");
List<String> list=Arrays.asList(split);
Random r = new Random();
while( list.size() > count ) {
return StringUtils.join(list, ", ");

I get this:

06-03 15:05:29.614: ERROR/AndroidRuntime(7737): java.lang.UnsupportedOperationException
06-03 15:05:29.614: ERROR/AndroidRuntime(7737): at java.util.AbstractList.remove(

How would be this the correct way? Java.15

Answer Source

Quite a few problems with your code:

On Arrays.asList returning a fixed-size list

From the API:

Arrays.asList: Returns a fixed-size list backed by the specified array.

You can't add to it; you can't remove from it. You can't structurally modify the List.


Create a LinkedList, which supports faster remove.

List<String> list = new LinkedList<String>(Arrays.asList(split));

On split taking regex

From the API:

String.split(String regex): Splits this string around matches of the given regular expression.

| is a regex metacharacter; if you want to split on a literal |, you must escape it to \|, which as a Java string literal is "\\|".



On better algorithm

Instead of calling remove one at a time with random indices, it's better to generate enough random numbers in the range, and then traversing the List once with a listIterator(), calling remove() at appropriate indices. There are questions on stackoverflow on how to generate random but distinct numbers in a given range.

With this, your algorithm would be O(N).

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download