Consider the below URL as an example.
Is there any method by which I can get "example.com" as an output. I know there is a method
HttpServletRequest, you can get individual parts of the URI using the methods below. You could also use them to reconstruct the URL piece by piece (to help debugging, or other tasks), like this:
// Example: http://myhost:8080/people?lastname=Fox&age=30 String uri = request.getScheme() + "://" + // "http" + ":// request.getServerName() + // "myhost" ":" + request.getServerPort() + // ":" + "8080" request.getRequestURI() + // "/people" (request.getQueryString() != null ? "?" + request.getQueryString() : ""); // "?" + "lastname=Fox&age=30"
request.getServerName() is the closest we got to you need.
For the "root domain", you'll have to work through the
String returned from
getServerName(). This is necessary because the Servlet would have no way of knowing ahead of time what you call "host" or what is just a domain like
.com (it could be a machine called
com in your network - and not just a suffix -, who knows?).
For the pattern you gave (one third+secondlevel+com/net), the following should get what you need:
String domain = request.getServerName().replaceAll(".*\\.(?=.*\\.)", ""));
The above will give the following input/outputs:
www.test.com -> test.com test1.example.com -> example.com a.b.c.d.e.f.g.com -> g.com www.com -> www.com com -> com