I'm using the following line of code to open an
Image
pictureBox1.Image = Image.FromFile("test.png");
pictureBox1.Image
Dispose()
Image
pictureBox1.Image
"test.png"
"test.png"
The approach with stream is not correct.
See here https://stackoverflow.com/a/8701748/355264
Correct code from above link:
Image img;
using (var bmpTemp = new Bitmap("image_file_path"))
{
img = new Bitmap(bmpTemp);
}