Ruwantha Ruwantha - 1 year ago 138
PHP Question

How to check the exception thrown correctly by PHPUnit?

I have div() in Cal class in my CalTest class has following methods to test the div().

public fucnction div($a,$b){
if($b == 0){
throw new Exception("Divided by zero");
return $a/$b

I can pass only testDiv() but testDiv2().

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I want to catch check wheather the exeption thrown correctly using PHPUnit. What am I missing here?? Your help is highly appreciated. Thank you!

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Answer Source

Just came across the same issue. For some reason PHPUnit will not allow you to set the expectedException to a generic exception and I am not sure why. Personally I opt to throw custom Exception codes rather than have to create a new exception class every time I want to differentiate exceptions.

Here is how I got around it:

 * @expectedException Test_Exception
public function testDivByZero()
    try {
        // Fyi you don't need to do an assert test here, as we are only testing the exception, so just make the call
        $result = $this->object->div(1,0);
    } catch (Exception $e) {
        if ('Exception' === get_class($e)) {
            throw new Test_Exception($e->getMessage(), $e->getCode());

 // Test_Exception.php
 class Test_Exception extends Exception
     public function __construct($message = null, $code = 0, Exception $previous = null)
         parent::__construct($message, $code, $previous);

This will allow you to engineer your code the way you want, and throw "generic" exceptions. Basically it just tests the Exception class and if it's generic, re-wrap it as a different exception; Test_Exception.

-- Update --

Found out yesterday that they have removed the generic exception restriction in the current "master" branch, which will be 3.7. Apparently the lead engineer has no desire of patching 3.6.

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