James Balajan James Balajan - 1 year ago 145
C Question

C lang: Segmentation fault 11

Recently I have been learning C from K&R's book, and then I came across an error. From what I know a segmentation fault is something to do with the memory, but it is not explained in the book. If you could please look at my code and explain what a segmentation fault is, and how this error came to be in my code. Thank you.

#include <stdio.h>

#define MAXLINE 256

int main () {
int c, ndigit[10], i, d, e;
char str[MAXLINE];
while ((c = getchar()) != EOF) {
if (c >= '0' && c <= '9')
++ndigit[c - '0'];}
for (i = 0; i <= 9; i++) {
for (d = 0; d < ndigit[i]; d++)
str[d] = '*';
str[d] = '\0';
printf("%d: %s\n",i,str);
for (e = 0; e <= MAXLINE; e++)
str[e] = '\0';
return 0;

Answer Source

You aren't initializing ndigit to zero, it's an array of garbage values that you then increment. It's likely ndigit's values are quite large, causing you to access str with a very large index, overflowing the bounds of the str array into invalid memory regions. The operating system sees you trying to access invalid memory regions and issues a segmentation fault, killing your program.

Also, as Jean-Fran├žois Fabre points out, your for-loop should go to < MAXLINE because the last valid index for str is MAXLINE - 1.

And as mszymborski points out, you likely want a newline ('\n') at the end of your print statement.

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