Javascript Question
JavaScript Sets lost reference but don't change size
I'm storing objects references inside my JavaScript Sets:
let set1 = new Set();
let obj = {};
Then if I use the has() method and the size property of the Set objects I get the next results:
console.log(set1.size) //it returns 1
console.log(set1.has(obj)) //it returns true
But, if I remove the reference of the object using the next code:
obj = null;
Then strange behaviour happens to me:
console.log(set1.size); //it returns 1 because they are Hard Sets.
console.log(set1.has(obj)); //it returns false
In the last line, why does it return false if the size is not changed? Then the reference is lost but the size is not changed.
Answer
In the last line, why does it return false if the size is not changed?
It returns size = 1 because it still holds one value (a reference to that object).
It returns false because it does not has a value that is equals to null.
But, if I remove the reference of the object using the next code:
You just overwrite a value of the variable. After that there is still one reference to the object left (inside the Set).
To remove an element from a Set you need to use Set.prototype.delete() method:
set1.delete(obj);
Presumably you need to do that while obj still holds a reference to the object.