- 4 years ago 218
Python Question

How do I escape forward slashes in python, so that open() sees my file as a filename to write, instead of a filepath to read?

Let me preface this by saying I'm not exactly sure what is happening with my code; I'm fairly new to programming.

I've been working on creating an individual final project for my python CS class that checks my teacher's website on a daily basis and determines if he's changed any of the web pages on his website since the last time the program ran or not.

The step I'm working on right now is as follows:

def write_pages_files():
Writes the various page files from the website's links
links = get_site_links()
for page in links:
site_page = requests.get(root_url + page)
soup = BeautifulSoup(site_page.text)
with open(page + ".txt", mode='wt', encoding='utf-8') as out_file:

The links look similar to this:


And the error I get is as follows:

with open(page + ".txt", mode='wt', encoding='utf-8') as out_file:
FileNotFoundError: [Errno 2] No such file or directory: '/site/sitename/class.txt'

How can I write the site pages with these types of names (/site/sitename/nameofpage.txt)?

Answer Source

you cannot have / in the file basename on unix or windows, you could replace / with .:

page.replace("/",".") + ".txt"

Python presumes /site etc.. is a directory.

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download