Mikhail Danshin Mikhail Danshin - 29 days ago 13
C# Question

The method or operation is not implemented

There is two forms. Form2 is derived from Form1.

But I have an issue with Form2 in design mode as shown on the screenshot below.

If I will comment this

this._presenter.Retrive();
it will work fine. Whats going on and how to solve the problem?

UPD:
If I will remove the throw new NotImplementedException(); and will insert, for example, MessageBox.Show("Test");, every time I will open Form2 the MessageBox will appears as though I run the application.

enter image description here

Form2

namespace InheritanceDemo
{
public partial class Form2 : Form1
{
public Form2()
{
InitializeComponent();
}
}
}


Form1

namespace InheritanceDemo
{
public partial class Form1 : Form
{
protected IPresenter _presenter;

public Form1()
{
InitializeComponent();
_presenter = new Presenters();
}

private void Form1_Load(object sender, EventArgs e)
{
this._presenter.Retrive();
}
}

public class Presenters : IPresenter
{
public void Retrive()
{
throw new NotImplementedException();
}
}

public interface IPresenter
{
void Retrive();
}
}

Answer

The main cause of error is what Fᴀʀʜᴀɴ and Yuval said:

throw new NotImplementedException();

But there is another important thing that you should pay attention to.

OP: If I will remove the throw new NotImplementedException(); and will insert, for example, MessageBox.Show("Test");, every time I will open Form2 the MessageBox will appears as though I run the application

If you notice, you will not receive this error in designer of Form1. But because your Form2 inherits from Form1 you receive this error.

It's because, when you open a form in designer, the designer makes an instance of base calss of your form to show your form. It means instead of creating an instance of Form2 it creates an instance of Form1 and run Form1 constructor and host it in design surface, and then deserializes the codes in InitializeComponent of Form2 and put components on design surface.

This is why you receive the error when you see your Form2 in designer, but you didn't receive any error while opening the Form1 in designer.

To solve the problem:

  • You can remove the implementation, and let the implementation be empty.
  • Also you can prevent the error by prevent running the code in Form_Load fd you are at design mode using DesignMode property, in Form1_Load:

    if (DesignMode) return;

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