fairy hunter fairy hunter - 2 years ago 116
Java Question

First Index of String in Infinite String - Java


I have an infinite String. The length of this string is infinite in our imagination and cannot be limited.Suppose that we have a sequence String like this:


The points after the number 9 actually representing the next sequence. So, it will be like this:



In this section, I want to explain about the requirement. The requirement is to find the index of first occurrence of input String (called n). Let me give you an example:

Example 1


First Index of n = 2

Example 2


First Index of n = 8


I have coded the algorithm to find the index of the String n. But the algorithm is only just a while loop to check the index of n and add the next sequence number one by one if index of n is not found. I want a better algorithm for this to find the index of first occurrence of n without relying on looping or less looping. At least, the algorithm don't run longer than 2 seconds if the value of n is big (Example: 123456790 or 62716855).


Snippet of my Code:

num +=start.toString();
start = start.add(BigInteger.ONE);

This is my full code: Full Code of My Code

Answer Source

Here's a general description of how to solve this problem. Translating it to Java can still be challenging.

Your input String is basically an infinite sequence of all the natural numbers 1 2 3 4 5 6 8 9 10 11 ....

I believe the point of the exercise is to identify the first sub-sequence of natural numbers of the input String that the substring n belongs to, and then calculate its index without actually constructing the large "infinite" String.

For that purpose, you have to try to split the substring n into an incrementing sequence of numbers having as few digits as possible.

First you have to check is the substring n creates a sequence of single digits numbers. That is the case, for example, if n == 345678 (note that n may contain both single digit and double digit numbers, for example n == 345678910, which you should also be able to identify).

If you fail in that step, you should look for a sequence of double digit numbers. That is the case, for example, if n == 33343536. Now, this could get trickier, since n == 2333435363 is also a sequence of two digit numbers, but the leading and trailing numbers of the sequence (32 and 37) are truncated.

If you fail again, you look for a sequence of 3 digit numbers.

If you don't find any sequence, you treat the entire substring n as a single number in the big String.

Now, suppose n is 199319941995, and you discovered in the previous step that the first number in the sequence is 1993. The remaining work is to calculate the index of the number 1993 in the input String. You know that the single digit numbers take 1*9 indices. The two digit numbers take 2*90 indices. The three digit numbers take 3*900 indices. The 3 digit numbers between 1000 and 1993 take 4*993 indices. Therefore the index of 1993 is 1*9+2*90+3*900+4*993, and that's the first index of the substring 199319941995.

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download