Aryan Aryan - 7 months ago 9
Java Question

How to check the similarity between two ints java

I am trying to create an app where the user has to memorise a random number (17 digits long) and then enter what s/he remembers. After generating the number, how do I check how similar they are i.e. 10 of the digits match so it is 58% similar.


Lets say you compare this two strings:

String number1; // users number
String number2; // your number

Since you said both will be 17 digit long, no need to take in account different sizes (then you should go from the end):

int matches = 0;
for (int i = 0;  i < number1.length(); i++) {
    if (number1.substring(i, i + 1).equals(number2.substring(i, i + 1))) matches++;

Another approach would be with char arrays:

char[] charArray1 = number1.toCharArray();
char[] charArray2 = number2.toCharArray();
for (int i = 0; i < charArray1.length; i++) {
    if (charArray1[i] == charArray2[i]) matches++;

Or by using Strings own array of chars (thanks @David Wallace):

for (int i = 0; i < charArray1.length; i++) {
    if (number1.charAt(i) == number2.charAt(i)) matches++;

Now, you calculate procent:

double procent = matches / (number1.length() * 1d) * 100;

You must multiply with double value of 1, so it doesn't calculates with int, this will force it to deal with doubles.