Nameless King - 1 year ago 37

C++ Question

`#include <iostream>`

#include <stdlib.h>

#include <algorithm>

#include <vector>

using namespace std;

// To Do: Finish this function

void yourFunction(int N, vector<float>&vec, float &m, float &n){

sort(vec.begin(), vec.end());

n=vec[0];

m=vec[N];

}

int main()

{

int N;

float m,n;

cout << "Please enter the length of array." << endl;

cin >> N;

float *p = (float*) malloc(sizeof(float)*N);

cout << "Please enter the numbers in your array.";

for(int i=0;i<N;i++)

cin >> *(p+i);

vector<float>vec(p[0],p[N-1]);

yourFunction(N,vec,m,n);

cout << "The largest number in your array is " << m << endl;

cout << "The smallest number in your array is " << n << endl;

return 0;

}

So this is a C++ program that is meant to identify the largest and smallest number in a user-inputted array. Code::Blocks 16, C++0X standards.

In its current state, however, when I input

`1 2 3 4 5`

https://i.stack.imgur.com/phktl.png

What is the problem here? I am an amateur coder and am probably making some dumb mistakes I didn't notice. :P

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Answer Source

Your biggest issue here is that

```
vector<float>vec(p[0],p[N-1]);
```

doesn't construct the vector you think it does. `p[0]`

and `p[N-1]`

are `floats`

, not pointers. So what you do is construct a vector with `p[0]`

number of elements all with the value of `p[N-1]`

. What you need if you want to construct a `vector`

for an array is

```
vector<float>vec(p,p + N);
```

You also have an issue with

```
m=vec[N];
```

Since `N`

is the size of the vector `vec[N]`

is not a valid element. It is one past the end. What you need is

```
m=vec[N - 1];
```

Do note that the vector is not needed here at all. You can just take a `float*`

in `yourFunction`

and sort that directly. That would look liked

```
void yourFunction(int N, float* data, float &m, float &n){
std::sort(data, data + N);
n = data[0];
m = data[N - 1];
}
int main()
{
int N;
float m,n;
cout << "Please enter the length of array." << endl;
cin >> N;
float *p = (float*) malloc(sizeof(float)*N);
cout << "Please enter the numbers in your array.";
for(int i=0;i<N;i++)
cin >> *(p+i);
yourFunction(N,p,m,n);
cout << "The largest number in your array is " << m << endl;
cout << "The smallest number in your array is " << n << endl;
return 0;
}
```

Even though you said you cannot change the code in `main`

I would also like to let you know that `new`

should be preferred over `malloc`

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