Wolfgang Müller Wolfgang Müller - 5 months ago 32
iOS Question

UTF8 Decoding with NSString

I am new to Objective-C and try to convert a malformed UTF8 encoded NSString to a wellformed one using the example on apples docs.

NSString *theString = @"Lügen"; //should be "ü"
NSString *asciiString = [[NSString alloc] initWithData:asciiData encoding:NSASCIIStringEncoding];

NSLog(@"Original: %@ (length %d)", theString, [theString length]);
NSLog(@"Converted: %@ (length %d)", asciiString, [asciiString length]);


Result:

Original: Lügen (length 6)
Converted: LA1/4gen (length 8)


This here is doing nothing:

NSString* str = [NSString stringWithUTF8String:
[theString cStringUsingEncoding:NSASCIIStringEncoding]];


This here crashes my app

NSString* str = [NSString stringWithUTF8String:
[theString cStringUsingEncoding:NSUTF8StringEncoding]];


Anyone any idea what I am doing wrong?

Answer
NSString *string = @"ü";
const char *c = [string cStringUsingEncoding:NSISOLatin1StringEncoding];
NSString *newString = [[NSString alloc]initWithCString:c encoding:NSUTF8StringEncoding];
NSLog(@"%@",newString); // ü

"Malformed UTF-8 sequence" means a sequence of bytes which are invalid in UTF-8. Your problem is unexpected results after parsing a string with a different encoding than the one used by the original author of the string.

Hexadecimal data C3 BC parsed with UTF-8 encoding is character ü. Instead you used Latin-1 encoding, which results in ü. Then you created a NSString from the Latin-1 parsed string, which means you converted the Latin-1 string to a UTF-16 string (which is the native format of NSString).

Representing a given data in different encodings shows up as different chars, but doesn't change the data. Converting to a different encoding does change the data in an attempt to reproduce the same characters. Example: The character ü is C3 83 C2 BC in UTF-8, but C3 BC in Latin-1. So I converted to the same chars in Latin-1 to get the original data, and then I parsed as UTF-8.

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