Polaris878 - 1 year ago 127

C++ Question

I have a pitch, roll, and yaw angles. I want to convert these to a directional vector.

Bonus points if you can give me a quaternion and/or matrix representation of this!

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Answer Source

Unfortunately there are different conventions on how to define these things (and roll, pitch, yaw are not quite the same as Euler angles), so you'll have to be careful.

If we define pitch=0 as horizontal (z=0) and yaw as counter-clockwise from the x axis, then the direction vector will be

x = cos(yaw)*cos(pitch) y = sin(yaw)*cos(pitch) z = sin(pitch)

Note that I haven't used roll; this is direction unit vector, it doesn't specify attitude. It's easy enough to write a rotation matrix that will carry things into the frame of the flying object (if you want to know, say, where the left wing-tip is pointing), but it's really a good idea to specify the conventions first. Can you tell us more about the problem?

**EDIT:**
(I've been meaning to get back to this question for two and a half years.)

For the full rotation matrix, if we use the convention above and we want the vector to yaw first, then pitch, then roll, in order to get the final coordinates in the world coordinate frame we must apply the rotation matrices in the reverse order.

First roll:

```
| 1 0 0 |
| 0 cos(roll) -sin(roll) |
| 0 sin(roll) cos(roll) |
```

then pitch:

```
| cos(pitch) 0 -sin(pitch) |
| 0 1 0 |
| sin(pitch) 0 cos(pitch) |
```

then yaw:

```
| cos(yaw) -sin(yaw) 0 |
| sin(yaw) cos(yaw) 0 |
| 0 0 1 |
```

Combine them, and the total rotation matrix is:

```
| cos(yaw)cos(pitch) -cos(yaw)sin(pitch)sin(roll)-sin(yaw)cos(roll) -cos(yaw)sin(pitch)cos(roll)+sin(yaw)sin(roll)|
| sin(yaw)cos(pitch) -sin(yaw)sin(pitch)sin(roll)+cos(yaw)cos(roll) -sin(yaw)sin(pitch)cos(roll)-cos(yaw)sin(roll)|
| sin(pitch) cos(pitch)sin(roll) cos(pitch)sin(roll)|
```

So for a unit vector that starts at the x axis, the final coordinates will be:

```
x = cos(yaw)cos(pitch)
y = sin(yaw)cos(pitch)
z = sin(pitch)
```

And for the unit vector that starts at the y axis (the left wing-tip), the final coordinates will be:

```
x = -cos(yaw)sin(pitch)sin(roll)-sin(yaw)cos(roll)
y = -sin(yaw)sin(pitch)sin(roll)+cos(yaw)cos(roll)
z = cos(pitch)sin(roll)
```

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