rednamalas - 1 month ago 9

Java Question

The title pretty much says it all. I'm working through the Liang java book, and I'm stuck on one of the problems. Here is my code.

`/*(Sum the digits in an integer) Write a program that reads an integer between 0 and`

1000 and adds all the digits in the integer. For example, if an integer is 932, the

sum of all its digits is 14.

Hint: Use the % operator to extract digits, and use the / operator to remove the

extracted digit. For instance, 932 % 10 = 2 and 932 / 10 = 93.

*/

import java.util.Scanner;

public class IntegerSum{

public static void main(String[]args) {

Scanner input = new Scanner(System.in);

System.out.print("Enter a number to have the sum of the digits calculated: ");

int integer = input.nextInt();

int tens = integer % 10;

int hundreds = (integer / 10) % 10;

int thousands = (integer / 100);

System.out.println("The sum of the digits of the number you entered is "

+ tens + hundreds + thousands);

}

}

Answer

adding brackets should fix it. it precalculates the sum before you concatenate into the string.

```
System.out.println("The sum of the digits of the number you entered is "
+ (tens + hundreds + thousands));
```