Muhammad Ahmed - 11 months ago 64

C++ Question

I have the following assignment:

We have the length of four sides. You have to determine if they can form a square. If not, determine if they can form a rectangle. If not, determine if they can form a quadrangle

Hints

Sorting the lengths will help us , so

this will be square`If L1 == L2 && L2 == L3 && L3 == L4`

this will be rectangle`If L1 == L2 && L3 == L4`

this will be quadrangle`If L1 + L2 + L3 > L4`

If it isn't one of them we will call it banana

Input:

The number of test cases, following a line with four positive integer numbers, between 0 and 2^30, the lengths.

Output:

One of four strings: ‘square’, ‘rectangle’, ‘quadrangle’ or ‘banana’.

Sample Input

`4`

10 8 7 6

9 1 9 1

29 29 29 29

5 12 13 7

Sample Output

`quadrangle`

rectangle

square

I don't know how to solve this. Here is my code so far:

`#include <iostream>`

using namespace std;

int main()

{

int L1; int L2; int L3; int L4;

cin>>L1>>L2>>L3>>L4;

cout<<"Enter the 4 lengths";

if(L1 == L2 && L2 == L3 && L3 == L4){

cout<<"You have choosed the square";

}

else if(L1 == L2 && L3 == L4|| L1==L3 && L2==L4){

cout<<"You have choosed the rectangle";

}

else if(L1 + L2 + L3 > L4){

cout<<"You have choosed the quadrangle";

}

else{

cout<<"It's Baanana";

}

return 0;

}

Answer Source

You are not ~~reading any input from the user, let alone~~ sorting the input. Also, you are not following the first requirement mentioned in the assignment, either (reading the number of test cases).

Try something more like this:

```
#include <iostream>
#include <algorithm>
using namespace std;
#define L1 Lengths[0]
#define L2 Lengths[1]
#define L3 Lengths[2]
#define L4 Lengths[3]
int main()
{
int NumTestCases, Lengths[4];
cout << "How many test cases? ";
cin >> NumTestCases;
for(int i = 0; i < NumTestCases; ++i)
{
cout << "Enter 4 lengths: ";
cin >> L1 >> L2 >> L3 >> L4;
std::sort(Lengths, Lengths+4);
if ((L1 == L2) && (L2 == L3) && (L3 == L4)) {
cout << "square" << endl;
}
else if (((L1 == L2) && (L3 == L4)) || ((L1 == L3) && (L2 == L4))) {
cout << "rectangle" << endl;
}
else if ((L1 + L2 + L3) > L4) {
cout << "quadrangle" << endl;
}
else {
cout << "banana" << endl;
}
}
return 0;
}
```