user548470 - 1 year ago 64

Javascript Question

I'm currently learning JavaScript using Marijn Haverbekes excellent book "Eloquent JavaScript". Now there is this exercise where you have to write a recursive function that returns the nth element of a nested list. If there is no such element, the function is supposed to return

`undefined`

`function nth(list, n) {`

if (!list)

return undefined;

else if (n == 0)

return list.value;

else

return nth(list.rest, n - 1);

}

So far, everything seems pretty clear to me. However, I don't really get what exactly

`if (!list) {}`

`list`

`n`

The complete excercise can be found here:

http://eloquentjavascript.net/04_data.html#p_7AnSuS26HF

Answer Source

This

```
if (!list)
```

Is a shorthand way of saying

```
if (list === false || list === 0 || list === '' || list === null || list === undefined || list !== list /* NaN */) ...
```

`!list`

will happen in when the list is shorter than `n`

elements.

```
// 4 is larger than the list length here, (2)
// !list will happen
nth({value: 'a', rest: {value: 'b', rest: null}}, 4)
//=> undefined
// 1 is not larger than the list length
// !list will not happen
// instead, n === 0 happens after recursing 1 time
nth({value: 'a', rest: {value: 'b', rest: null}}, 1)
//=> 'b'
```