Template specialization for enum

Question

Is it possible to specialize a templatized method for enums?

Something like (the invalid code below):

template <typename T>

void f(T value);



template <>

void f<enum T>(T value);

In the case it's not possible, then supposing I have specializations for a number of types, like

int

,

unsigned int

,

long long

,

unsigned long long

, etc, then which of the specializations an enum value will use?

Answer 1

You can use std::enable_if with std::is_enum from <type_traits> to accomplish this.

In an answer to one of my questions, litb posted a very detailed and well-written explanation of how this can be done with the Boost equivalents.

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