Link - 5 months ago 11x

Ruby Question

Possible Duplicate:

Turning long fixed number to array Ruby

Well, I have to iterate over the digits of a integer in Ruby. Right now I was just splitting it up into an array, and then iterating over that. However I was wondering if there was a faster way to do this?

Answer

The shortest solution probably is:

```
1234.to_s.chars.map(&:to_i)
#=> [1, 2, 3, 4]
```

Here's a more orthodox mathematical approach:

```
class Fixnum
def digits(base: 10)
quotient, remainder = divmod(base)
quotient == 0 ? [remainder] : [*quotient.digits(base: base), remainder]
end
end
1234.digits #=> [1, 2, 3, 4]
0644.digits(base: 8) #=> [6, 4, 4]
0x3f.digits(base: 16) #=> [3, 15]
```

Source (Stackoverflow)

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