Dustin Silk Dustin Silk - 1 year ago 127
CSS Question

Position element over background image. But the BG img changes size with the window. CSS

I have a background image which changes size to the windows size, and I need to position an element on it so that it is always in the same place relative to the background image.



background:url("http://placehold.it/100x100") no-repeat center center fixed;

The background image covers the entire background and changes size with the window but keeps proportions by having some overlay.

EDIT - 2016

My solution to this with pure CSS is to position the element in the middle and then offset it correctly using calc function. And then to resize it accordingly i use the vmin value:

$offset-top: ...;
$offset-left: ...;

.element {
top: 50%;
left: 50%;
transform: translate(calc(-50% + #{$offset-top}), calc(-50% + #{$offset-top}));
width: 50vim;
height: 50vim;

Answer Source

What you are asking for is not a trivial thing at all, it basically involves figuring out how background-size:cover works and then positioning your element using JavaScript. Due to the nature of background-size:cover how the image can flow out of the x-axis or y-axis this cannot be done with CSS.

Here is my solution to the problem, on load and resize it calculates the scale of the image and the x or y offset and draws the pointer at the relevant location.

jsFiddle (red dot in Google's red 'o')

enter image description here


<div id="pointer"></div>


body {
    background:url(https://www.google.com.au/images/srpr/logo4w.png) no-repeat center center fixed;

#pointer {


var image = { width: 550, height: 190 };
var target = { x: 184, y: 88 };

var pointer = $('#pointer');


function updatePointer() {
    var windowWidth = $(window).width();
    var windowHeight = $(window).height();

    // Get largest dimension increase
    var xScale = windowWidth / image.width;
    var yScale = windowHeight / image.height;
    var scale;
    var yOffset = 0;
    var xOffset = 0;

    if (xScale > yScale) {
        // The image fits perfectly in x axis, stretched in y
        scale = xScale;
        yOffset = (windowHeight - (image.height * scale)) / 2;
    } else {
        // The image fits perfectly in y axis, stretched in x
        scale = yScale;
        xOffset = (windowWidth - (image.width * scale)) / 2;

    pointer.css('top', (target.y) * scale + yOffset);
    pointer.css('left', (target.x) * scale + xOffset);
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