Artificial Mind Artificial Mind - 1 year ago 107
C++ Question

Why does unsigned int not work in constructor syntax?

So this question might be a little odd, but why is the following illegal in C++?

auto x = unsigned int(0);

Whereas the following are all ok:

auto y = int(0);
auto z = unsigned(0);
auto w = float(0);

or in general

auto t = Type(... c-tor-args ...);

(with the exception of
unsigned int

Answer Source

This is explicit type conversion, and functional cast expression consists of a single-word type specifier is not valid.

(emphasis mine)

The functional cast expression consists of a simple type specifier or a typedef specifier (in other words, a single-word type name: unsigned int(expression) or int*(expression) are not valid), followed by a single expression in parentheses. This cast expression is exactly equivalent to the corresponding C-style cast expression.

You can change it to c-style cast expression or static_cast:

auto x1 = (unsigned int)(0);
auto x2 = static_cast<unsigned int>(0);
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