John Ebenezer -4 years ago 42
Python Question

# get the count of elements of tuples of your own...not just the range or sequence

The below code is running for first three elements of the tuple of this list

``````SS1=[(1, 2, 3, 4, 5), (1, 2, 3, 4, 6), (1, 2, 3, 5, 6), (1, 2, 4, 5, 6), (1, 3, 4, 5, 6), (2, 3, 4, 5, 6)]

from collections import Counter
c = Counter(elem[0:3] for elem in SS1)

for k, v in c.items():
if (v > 0):
print(k,v)
``````

and the output is:

``````(1, 2, 3) 3
(1, 2, 4) 1
(1, 3, 4) 1
(2, 3, 4) 1
``````

But my expectation is not just for first three tuple...i want the counter for tuple
`(0,2,3)`
or tuple
`(1,2,4)`
likewise i can pass any three position of the tuple and get the count of it... How can I do this?

If what i understood from your question is correct, the code below will solve your issue:

``````SS1=[(1, 2, 3, 4, 5), (1, 2, 3, 4, 6), (1, 2, 3, 5, 6), (1, 2, 4, 5, 6), (1, 3, 4, 5, 6), (2, 3, 4, 5, 6)]

from collections import Counter

def get_new_list(a, pos):
# Check if any element in pos is > than the length of the tuples
if any(k >= len(min(SS1, key=lambda x: len(x))) for k in pos):
return

for k in a:
yield tuple(k[j] for j in pos)

def elm_counter(elm):
if not len(elm):
return

c = Counter(elm)
for k, v in c.items():
if v > 0:
print(k, v)

elm = list(get_new_list(SS1, (0, 2, 4)))
elm_counter(elm)
print('---')
elm = list(get_new_list(SS1, (1, 2, 4)))
elm_counter(elm)
``````

Output:

``````(1, 3, 5) 1
(1, 3, 6) 2
(1, 4, 6) 2
(2, 4, 6) 1
---
(2, 3, 6) 2
(2, 3, 5) 1
(3, 4, 6) 2
(2, 4, 6) 1
``````
Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download