Code Eyez Code Eyez - 1 month ago 9
C++ Question

C++ argv[] not being passed fully

// Type the determine year in the command line as an argument.
// This program then prints the months and days for that year.

//Known Error argv[1] = the first digit of year,

#include "stdafx.h"
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;

void printYear(int year);

int _tmain(int argc, char *argv[]){
string str;//varible used to exit the program

if (argc == 1 ){//checks to see if the years were inputted corrected
std::cout << "Please input Year in the command line. Exiting.." << std::endl;
cout << "Please type anything to continue..." << endl;
cin >> str;
return 1;

int Year = 1982;
int numYears = argc-1;

cout << "Number of Argments Loaded : " << numYears << endl;
for (int x = 1; x <= numYears; x++){
Year = atoi(argv[x]);
cout << "Year : " << argv[x] << endl;
cout << "Year is " << Year << endl;

cout << "Please type anything to continue..." << endl;
cin >> str;
return 0;

I'm currently learning C++ and this is one of my assignments. I just spent a better half of a day looking into this to no avail.

printYear() has been tested with numerous years and is functional. The only remanding error left is with argv[]. It only returns the first digit of the year inputted, which is fine if you want to research years 0-9. Any tips or trick you guys mind passing me? (I'm using Microsoft Visual Studio fyi)

Command line

calender.exe 1982

returns with

Number of Arguments Loaded : 1
Year : 1
Year is 1

Repetitive code I know but I'm troubleshooting.

Dan Dan

The problem is _tmain. If you have unicode enabled it tries to give you wide (UTF-16) characters, so every other character will be \0. To fix this you want to call it main instead.