jared - 1 month ago 9x

Javascript Question

FYI: random == pseudo-random

A. when generating uniformly-random numbers, I can specify a range, i.e.:

`(Math.random()-Math.random())*10+5`

//generates numbers between -5 and 15

B. generating a set of random values with a version of Gaussian-esque normal randomness:

`//pass in the mean and standard deviation`

function randomNorm(mean, stdev) {

return Math.round((Math.random()*2-1)+(Math.random()*2-1)+(Math.random()*2-1))*stdev+mean);

}

//using the following values:

{

mean:400,

standard_deviation:1

//results in a range of 397-403, or +-range of 3

},

{

mean:400,

standard_deviation:10

//results in a range of 372-429, or +-range of 30

},

{

mean:400,

standard_deviation:25

//results in a range of 326-471, or +-range of 75

}

each one gives me a range of approximately standard_deviation*(+-3) (assuming I left the program running longer).

C. I can calculate this range as follows:

- assuming I want a range from 300-500, so var total_range = 200;
- my mean is 400, my +-range is total_range/2 (var r = 100)
- so standard_deviation would be r/3 or in this case 33.333.

This seems to be working, but I have no idea what I'm doing with math so I feel like an idiot, this solution feels kludgy and not totally accurate.

My question:

is there some formula that I'm dancing around that can help me here? my requirements are as follows:

- must be able to define a range of numbers accurately.
- must be done in JavaScript, as efficiently as possible.

I think maybe I'm close but it's not quite there.

Answer

Subtracting two random numbers doesn't give you a normal distribution, it will give you numbers that decline linearly on both sides of zero. See the red diagram in this fiddle:

http://jsfiddle.net/Guffa/tvt5K/

To get a good approximation of normal distribution, add six random numbers together. See the green diagram in the fiddle.

So, to get normally distributed random numbers, use:

```
((Math.random() + Math.random() + Math.random() + Math.random() + Math.random() + Math.random()) - 3) / 3
```

This method is based on the central limit theorem, outlined as the second method here: http://en.wikipedia.org/wiki/Normal_distribution#Generating_values_from_normal_distribution

Source (Stackoverflow)

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