Kevin Klarić Kevin Klarić - 1 year ago 59
Python Question

Return the "valid" numbers

I need to write a function in python, which returns the valid measurements for a list of numbers. A measure is invalid, if the closest other measurement is less that 0.1 second away. Also, the output list should be the same length as the length of the input list.


[5.1, 5.6, 6.0, 10.34, 10.37, 10.45, 12.5]
should return
[True, True, True, False, False, False, True]

I have approached the problem in the following fashion:

list = [5.1, 5.6, 6.0, 10.34, 10.37, 10.45, 12.5]
newlist = []

for i, j in zip(list, list[1:]):
if j - i >= .1:

The problem is that this returns the following list:
[True, True, True, False, False, True]
with one
measurement missing.

How can I write this code differently?

Answer Source

Your assumption is incorrect. There's only 2 false measurements. The one at 10.37 and the one at 10.45. The measurement at 10.34 is OK since it happens several seconds after the previous one.

Your result has 1 less value than the input list because you're comparing values 2 by 2.

It's a typical "intervals & values" problem. There's one less interval than values.

Write your test like this for better performance (list comprehension):

measures = [5.1, 5.6, 6.0, 10.34, 10.37, 10.45, 12.5]
print([measures[i+1]-measures[i]>0.1 for i in range(len(measures)-1)])

[True, True, True, False, False, True]

(your code creates a lot of useless temporary lists. Also avoid using list as a variable)

However, if you want to invalidate all measurements which are too close, no fancy stuff, with sliding window:

measures = [5.1, 5.6, 6.0, 10.34, 10.37, 10.45, 12.5]
result = [True] * len(measures)

for i in range(len(measures)-1):
    validity = (measures[i+1]-measures[i])>0.1
    if result[i]:  # don't overwrite an already invalidated value
        result[i] = validity
    result[i+1] = validity


[True, True, True, False, False, False, True]


  • creates a result array of the size of the input array (* operator, nice)
  • iterates through all elements of the list but the last one
  • compares current value and the "next" value to compute a validity flag (True or False)
  • if current result is already False, it means that previous iteration already invalidated it, leave as-is, else set to validity
  • set "next" result to validity (i+1 index)

No temporary list creation, should be fast enough.

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