I'm currently teaching myself Python and was just wondering (In reference to my example below) in simplified terms what the sys.argv represents. Is it simply asking for an input?
# import modules used here -- sys is a very standard one
# Gather our code in a main() function
print ('Hello there', sys.argv)
# Command line args are in sys.argv, sys.argv ..
# sys.argv is the script name itself and can be ignored
# Standard boilerplate to call the main() function to begin
# the program.
if __name__ == '__main__':
I note that previous answers made lots of assumptions about the user's knowledge. This answer attempts to answer the question at a more tutorial level.
For every invocation of Python,
sys.argv is automatically a list of strings representing the arguments (as separated by spaces) on the command-line. The name comes from the C programming convention in which argv and argc represent the command line arguments.
You'll want to learn more about lists and strings as you're familiarizing yourself with Python, but it the meantime, here are a few things to know.
You can simply create a script that prints the arguments as they're represented. It also prints the number of arguments, using the
len function on the list.
from __future__ import print_function import sys print(sys.argv, len(sys.argv))
The script requires Python 2.6 or later. If you call this script
print_args.py, you can invoke it with different arguments to see what happens.
> python print_args.py ['print_args.py'] 1 > python print_args.py foo and bar ['print_args.py', 'foo', 'and', 'bar'] 4 > python print_args.py "foo and bar" ['print_args.py', 'foo and bar'] 2 > python print_args.py "foo and bar" and baz ['print_args.py', 'foo and bar', 'and', 'baz'] 4
As you can see, the command-line arguments include the script name but not the interpreter name. In this sense, Python treats the script as the executable. If you need to know the name of the executable (python in this case), you can use
You can see from the examples that it is possible to receive arguments that do contain spaces if the user invoked the script with arguments encapsulated in quotes, so what you get is the list of arguments as supplied by the user.
Now in your Python code, you can use this list of strings as input to your program. Since lists are indexed by zero-based integers, you can get the individual items using the list syntax. For example, to get the script name:
script_name = sys.argv # this will always work.
Although that's interesting to know, you rarely need to know your script name. To get the first argument after the script for a filename, you could do the following:
filename = sys.argv
This is a very common usage, but note that it will fail with an IndexError if no argument was supplied.
Also, Python lets you reference a slice of a list, so to get another list of just the user-supplied arguments (but without the script name), you can do
user_args = sys.argv[1:] # get everything after the script name
Additionally, Python allows you to assign a sequence of items (including lists) to variable names. So if you expect the user to always supply two arguments, you can assign those arguments (as strings) to two variables:
user_args = sys.argv[1:] fun, games = user_args # len(user_args) had better be 2
So, in final answer to your specific question,
sys.argv represents the first command-line argument (as a
string) supplied to the script in question. It will not prompt for input, but it will fail with an IndexError if no arguments are supplied on the command-line following the script name.