Ben Carlson - 9 months ago 56

R Question

I'd like to know if it's possible to use dplyr to expand the rows of a data.frame based on criteria in each row. If it's not possible in dplyr I'd be happy for any solution!

Here is a sample of my data

`data.frame(plot=rep(c(6,7),each=4),`

trans=rep(c("0,0","0,100","100,100","100,0"),2),

length_m=c(350,200,200,50,45,200,125,75) )

plot trans length_m

6 0,0 350

6 0,100 200

6 100,100 200

6 100,0 50

7 0,0 45

7 0,100 200

7 100,100 125

7 100,0 75

The data above represent two plots. In general each of my plots plot has 1 to 4 transects, identified by 0,0; 0,100; 100,100; or 100,0 (the plots above both have all four possible transects). Each transect has a length given by length_m. What I'd like to do is to divide each transect by length L, and make one row for each new transect. If the final transect is < L, then that distance should be added to the previous transect.

So, if L = 100, the above dataset would look like this

`plot trans length_m`

6 0,0_0 100

6 0,0_100 100

6 0,0_200 150

6 0,100_0 100

6 0,100_100 100

6 100,100_0 100

6 100,100_100 100

6 100,0_0 50

7 0,0_0 45

7 0_100_0 100

7 0,100_100 100

7 100,100_0 125

7 100,0_0 75

Note that 6, 0,0, which was 350 meters long, is split into sections 0,100 & 200, with lengths 100,100 & 150, while 6, 100,0 which was 50 meters long is just a single section 0 and is still 50 meters long.

I've tried a couple of different ways to make this work but nothing that is worth posting, so any help would be much appreciated!

Answer Source

Here's a data table solution, assuming your original data is in a data frame `df`

.

```
df$trans <- as.character(df$trans) # need trans to be char, not factor
library(data.table)
dt <- data.table(df)
L <- 100
f <- function(x) { # implements the partitioning
if (x<L) return(x)
y <- rep(L,as.integer(x/L))
y[length(y)] <- y[length(y)]+x-sum(y)
return(y)
}
result <- dt[,list(length_m=f(length_m)),by=list(plot,trans)]
result[,trans:=paste(trans,L*(0:(.N-1)),sep="_"),by=list(plot,trans)]
result
# plot trans length_m
# 1: 6 0,0_0 100
# 2: 6 0,0_100 100
# 3: 6 0,0_200 150
# 4: 6 0,100_0 100
# 5: 6 0,100_100 100
# 6: 6 100,100_0 100
# 7: 6 100,100_100 100
# 8: 6 100,0_0 50
# 9: 7 0,0_0 45
# 10: 7 0,100_0 100
# 11: 7 0,100_100 100
# 12: 7 100,100_0 125
# 13: 7 100,0_0 75
```