vowels = ('a', 'e', 'i', 'o', 'u')
for c in word:
if c in vowels:
res = word.replace(c,"")
Here is a version using a list instead of a generator:
def removeVowels(word): letters =  # make an empty list to hold the non-vowels for char in word: # for each character in the word if char.lower() not in 'aeiou': # if the letter is not a vowel letters.append(char) # add it to the list of non-vowels return ''.join(letters) # join the list of non-vowels together into a string
You could also write it just as
''.join(char for char in word if char.lower() not in 'aeiou')
Which does the same thing, except finding the non-vowels one at a time as
join needs them to make the new string, instead of adding them to a list then joining them at the end.
If you wanted to speed it up, making the string of values a
set makes looking up each character in them faster, and having the upper case letters too means you don't have to convert each character to lowercase.
''.join(char for char in word if char not in set('aeiouAEIOU'))