Using decorators on lambdas in Python?

Question

Is there any syntax for using a decorator on a lambda function in Python? Example:

def simpledecorator(f):

     def new_f():

         print "Using a decorator: "

         f()

     return  new_f



@simpledecorator

def hello():

    print "Hello world!"

Results in this output:

>>> hello()

Using a simple decorator:

Hello world!

Yet when I try the same with a lambda:

@anotherdecorator

f = lambda x: x * 2

I get this:

  File "<stdin", line 2

    f = lambda x: x * 2

    ^

 SyntaxError: invalid syntax

I feel like this might be a good way to make lambdas more versatile by allowing statements to be "injected" into them. But if there exists such a feature, I don't know what the syntax is.

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Answer 1

f = anotherdecorator(lambda x: x * 2)

Using decorators on lambdas in Python?

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