Tony The Lion Tony The Lion - 1 year ago 259
C++ Question

const pointer assign to a pointer

Why can I not do this:

char* p = new char[10];

void SetString(char * const str)
p = str;


I have a const pointer to a char, why can I not assign the const pointer to another pointer?

It just seems illogical, as by assigning it to another pointer, you are not essentially violating the const-ness of the char pointer. Or are you?

When I compile this it says "error C2440: '=' : cannot convert from 'char *const *__w64 ' to 'char *'"

(I'm attempting to understand a concept from a book I'm reading. Just cannot get the code to compile.


int _tmain(int argc, _TCHAR* argv[])

MyString *strg = new MyString(10);
strg->SetString("Hello, ");

MyString *secondstr = new MyString(7);

strg->concat(*secondstr, *strg);



#include "MyStringClass.h"
#include <string.h>
#include "stdafx.h"

#include "MyStringClass.h"

void MyString::concat(MyString& a, MyString& b)
len = a.len + b.len;
s = new char[len + 1];
strcpy(s, a.s);
strcat(s, b.s);
delete [] s;


void MyString::SetString(char * const str)
s = str;

MyString::MyString(int n)
s = new char[n+1];
s[n+1] = '\0';
len = n;


#include <string.h>
#include <stdio.h>

class MyString
char* s;
int len;
MyString(int n = 80);

void SetString (char * const str);

void concat (MyString& a, MyString& b);

Answer Source

There is difference between constant pointer and pointer to constant. Constant pointer is a pointer (a number - memory address) that cannot be changed - it always point to the same object given via initialization:

int * const const_pointer = &some_int_var; // will be always pointing to this var
const_pointer = &some_other_var; // illegal - cannot change the pointer
*const_pointer = 2; // legal, the pointer is a pointer to non-const

Pointer to constant is a pointer whose pointed value cannot be changed:

const int * pointer_to_const = &some_int_var; // doesn't have to be always pointing to this var
pointer = &some_other_var; // legal, it's not a constant pointer and we can change it
*pointer = 2; // illegal, pointed value cannot be changed

You can always assign constant to variable i.e. const pointer to non-const pointer (a). You can cast pointer to non-const to a poionter to const (b). But you cannot cast pointer to const to a poionter to non-const (c):

int * pointer;
int * const const_pointer = &var;
const int * pointer_to_const;

/* a */
pointer = const_pointer; // OK, no cast (same type)

/* b */
pointer_to_const = pointer; // OK, casting 'int*' to 'const int*'

/* c */
pointer = pointer_to_const; // Illegal, casting 'const int*' to 'int*'

[EDIT] Below, this is not standard c++. However, this is common.[/EDIT]
String literal


is converted to constant pointer to const (const char * const):

char *pointer = "Hello"; // Illegal, cannot cast 'const char*' to 'char*'
char * const const_pointer = "Hello"; // Illegal, cannot cast 'const char*' to 'char*'
const char * pointer_to_const = "Hello"; // OK, we can assign a constant to a variable of the same type (and the type is 'const char*')
"Hello" = pointer_to_const; // Illegal cannot re-assign a constant

In above examples the second is your case. You tried to initialize pointer-to-non-const with a pointer-to-const when passing string literal as argument of your function. No matter if these pointers are constants or not, it's matter what do they point to.

1) If you cast a pointer of some type to a pointer of another type, you cannot cast pointer-to-const to pointer-to-non-const.
2) If you have constant pointer, the same rules applies as to other constants - you can assign a constant to a variable but you cannot assign a variable to a constant (except initializing it).

As GMan pointed out, the C++98 standard (ยง4.2/2) allows to implicitly cast string literals (which are constant char arrays) to a non-const char pointer. This is because of backward compatibility (in C language there are no constants).

Of course such a conversion can lead to mistakes and compilers will violate the rule and show an error. However, GCC in compatibility mode shows only a warning.

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