Jari Flederick Jari Flederick - 2 months ago 6
HTML Question

php conflicting with html

So i have a file with PHP and HTML in it. The HTML works fine but when i enter the PHP it does not render anything for some reason. See code for beter refrence.
Also logs don't really say anything about the issue.

This fails to do anything



<?php

echo $_POST['naam'];
die();

?>

<!DOCTYPE html>
<html>
<head>
<title>Scouts Permeke</title>
<link rel="stylesheet" type="text/css" href="siteStyle.css">
</head>
<body>
<H2>Login</H2>

<form action="login.php" method="POST">
<input name="naam" type="text" id="naam" class="form-control" placeholder="Gebruikersnaam"/><br>
<input name="psw" type="password" id="psw" class="form-control" placeholder="Passwoord"/><br>
<button type="submit">Login</button>
</form>
</body>
</html>





But this shows my HTML as intended.



<!DOCTYPE html>
<html>
<head>
<title>Scouts Permeke</title>
<link rel="stylesheet" type="text/css" href="siteStyle.css">
</head>
<body>
<H2>Login</H2>

<form action="login.php" method="POST">
<input name="naam" type="text" id="naam" class="form-control" placeholder="Gebruikersnaam"/><br>
<input name="psw" type="password" id="psw" class="form-control" placeholder="Passwoord"/><br>
<button type="submit">Login</button>
</form>
</body>
</html>




Answer

You need to check if the variable is actually set, otherwise it will always print out the content of $_POST['naam'] without bothering if the user already inputted data and pressed the Submit-button.

if(isset($_POST['naam'])) {
  echo $_POST['naam'];
  die();
}