Prince Sharma - 1 year ago 88
Python Question

# Calculate time difference using python

I am wondering if there is a way or builtin library available to find the difference in time from two string input.

What I mean is, if I have 2 input strings:

1. '2013-10-05T01:21:07Z'

2. '2013-10-05T01:21:16Z'

how can I can calculate the difference in time and print it as output.

I know it sounds a bit silly but any help on this is appreciated.

Parsing your strings using `strptime()`:

``````a = time.strptime('2013-10-05T01:21:07Z', '%Y-%m-%dT%H:%M:%SZ')
b = time.strptime('2013-10-05T01:21:16Z', '%Y-%m-%dT%H:%M:%SZ')
``````

This will parse the given time strings as local times (setting daylight savings (DST) to automatic), and the results are time structs. These still reflect whether DST was explicitly off (0), on (1), or implicitly automatic (-1). Convert these to a float (seconds since 1970-01-01):

``````a = time.mktime(a)
b = time.mktime(b)
``````

Then compute the difference (in seconds):

``````d = b - a
``````

And convert them to days/hours/minutes/seconds:

``````days = int(d) / 86400
hours = int(d) / 3600 % 24
minutes = int(d) / 60 % 60
seconds = int(d) % 60
``````

The last block only works properly for positive differences, so be careful not to swap the `a` and `b` ;-)

But @J.F.Sebastian correctly pointed out that this might not be what you intended. It seems from the notation that your strings describe a UTC time, not a local time. For mere time differences this is relevant in case your time spans over a DST switch. In this case it would of course result in a time difference one hour too great or one hour too small (because UTC is always without DST).

To avoid this, you can set the DST flag from automatic (-1) to a fixed value (e. g. 0 for off) and use these values:

``````a = time.mktime(a[:-1] + (0,))  # switch DST to off
b = time.mktime(b[:-1] + (0,))
``````

Or, also as @J.F.Sebastian pointed out, you could forget about the `time` module and instead use `datetime.datetime` which is unaware of the DST aspect:

``````a = datetime.datetime.strptime('2013-10-05T01:21:07Z', '%Y-%m-%dT%H:%M:%SZ')
b = datetime.datetime.strptime('2013-10-05T01:21:16Z', '%Y-%m-%dT%H:%M:%SZ')
``````

Then the results are `datetime` objects which can be subtracted directly to get a `timedelta` object which represents such a time difference as you want it. Printing it will result in sth like `0:00:05` which might well be exactly what you are looking for.

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