Sergei Levashov Sergei Levashov - 4 months ago 30
Java Question

Java adding modified tokens into string

I currently have a program that individually converts tokens of a string into their piglatin counterparts. However, the program needs to insert them back into the string they were taken with, with ALL of the original characters in it.

Hasta la vista baby. - the Terminator.







These are all of the words and their conversions. I tried a method directly placing them back in, however accounting for missing characters and different length made it hard for me to do that. I tried to insert characters based on the length of each token added up, but that ran into complications when there were more than 1 whitespace character. How would I insert these words back into the string so it looks like this:

Astahay alay istavay abybay. - ethay Erminatortay

PigOrig = key.readLine();
String[] PigSplit = PigOrig.split("\\W+");
for(int i = 0; i < PigSplit.length; i++)
if(PigSplit[i] != null)
FinalStr += Piggy.vowelOut(PigSplit[i]); // VowelOut returns the converted word only, no trailing whitespace or punctuation
lengthtot += PigSplit[i].length();
FinalStr += PigOrig.charAt(lengthtot); // attempt at adding up the words and inserting the original punctuation that was in the string PigOrig
lengthtot ++;



If I understand your question, it is 'how do I replace each word with its translation in a string?' The simplest way is to use String.replace.

So if you have created a translate method then you could do something like:

String line = key.readLine();
for (String word: line.split("\\W+"))
    line = line.replace(word, translate(word));

The advantage of this approach is that you are replacing the words in the original string not putting the words back together again.

Also note that it might be easier to translate just using pattern matching. For example:

private String translate(String word) {
    Matcher match = Pattern.compile("(\\w*)([aeiou]\\w*)").match(word);
    if (match.matches())
        return + + "ay";
        return word;