Adrien Weidemann Adrien Weidemann - 5 months ago 33
Java Question

"Malformed JSON" from http get request

I get some data on an URL. There's my server script :

$db = null;
$results = "{}";


/* Query */
if($db != null) {
$stmt = $db->prepare("SELECT category, category_color FROM categories ORDER BY category");
$results = $stmt->fetchAll(PDO::FETCH_ASSOC);

/* Close db connection */
$db = null;

echo json_encode($results);

Soooo.. I get theses datas on my Android App. This is what my App get from the script :

{"category":"Video games","category_color":"red"}]

And there's my App code, to get my datas (this is my first App so some code found on Internet helped me) :

protected String doInBackground(String... urls) {
String url = urls[0];
String parsedString;
HttpURLConnection c = null;
try {
URL u = new URL(url);
c = (HttpURLConnection) u.openConnection();
c.setRequestProperty("Content-type", "application/json");
c.setRequestProperty("Content-length", "0");
int status = c.getResponseCode();

switch (status) {
case 200:
case 201:
//Do stuff to parse my JSON to an HashMap

} catch(IOException ex) {
Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
} finally {
if (c != null) {
try {
} catch (Exception ex) {
Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
return null;

I've tried a lot of stuff to parse theses datas into a HashMap ([category, category_color] for each element) like this :

StringBuilder sb = new StringBuilder();
String line;

try {
BufferedReader r1 = new BufferedReader(new InputStreamReader(c, "UTF-8"));
while ((line = r1.readLine()) != null) {
} finally {
return sb.toString();

I found this result everytime for each response on Stack. But when I tried this code, my console has printed : E/JSON Task: Cound not parse malformed JSON when I try to do : "JSONObject json = new JSONObject(result);

So, there is my final question :

What is the best way to get an HashMap from a JSON get from my php script ? A simple link can be useful, but at the moment, I can't found a clean working answer.


Best way to get data from php script is to create array

  "result": [
      "category": "Animals",
      "category_color": "green"
      "category": "Art",
      "category_color": "orange"

you can get data in above format by following script

$return_arr = array();

$fetch = mysql_query("SELECT category, category_color FROM categories ORDER BY category"); 

while ($row = mysql_fetch_array($fetch, MYSQL_ASSOC)) {
    $row_array['category'] = $row[0];
    $row_array['category_color'] = $row[1]; 


echo json_encode($return_arr);

prase data by following code

JSONObject jsonObject = new JSONObject(response); // here response is what you get from php script which is shown at top 
JSONArray message = jsonObject.getJSONArray("result");

for (int i = 0; i < message.length(); i++) {
                    Model model = new Model();
                    JSONObject temp = message.getJSONObject(i);
                    String category = temp.getString("category");
                    String category_color = temp.getString("category_color");

// create array or harshmap to store all data