gameOne gameOne - 11 days ago 6
MySQL Question

Subtract results of two Select queries in Mysql

I have written two mysql queries, one fetches me the total users(registered) present in a particular month of the year and the other fetches the active users in that particular month of the year. I need to find the number of inactive users for that year. For this, I was thinking of subtracting the totalUsers and the activeUsers columns obtained through two separate queries.
Below are the queries

1. Fetch Total Registered users

set @numberOfUsers := 0;
SELECT T.createdMonth, T.monthlyusers, (@numberOfUsers := @numberOfUsers + T.monthlyusers) as totalUsers
FROM
(
SELECT month(from_unixtime(u.createdDate)) as createdMonth, count(u.id) as monthlyusers
FROM user u
where year(from_unixtime(u.createdDate)) = '2016'
group by month(from_unixtime(u.createdDate))
) T;

2. Fetch Active Users

select month(from_unixtime(lastActive)), (count(u.id)) as activeUsers from user u
where year(from_unixtime(lastActive)) = '2016'
group by month(from_unixtime(lastActive));


I need to subtract activeUsers from totalUsers. How do i achieve this?

Answer

you can simply subtract two query or merge

select (select query) - (select query);

SET @numberOfUsers := 0; 

SELECT l.totalUsers-a.monthlyusers FROM (SELECT T.createdMonth, 
T.monthlyusers, (@numberOfUsers := @numberOfUsers + T.monthlyusers) AS totalUsers 
FROM 
(
SELECT MONTH(FROM_UNIXTIME(u.createdDate)) AS createdMonth, COUNT(u.id) AS monthlyusers
FROM USER u 
WHERE YEAR(FROM_UNIXTIME(u.createdDate)) = '2016'  
GROUP BY MONTH(FROM_UNIXTIME(u.createdDate))    
) T ) l,(SELECT MONTH(FROM_UNIXTIME(lastActive)), (COUNT(u.id))  AS  activeUsers FROM USER u 
WHERE YEAR(FROM_UNIXTIME(lastActive)) = '2016' 
GROUP BY MONTH(FROM_UNIXTIME(lastActive))) a ;
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