dlofrodloh dlofrodloh -5 years ago 111
PHP Question

Regex replace a string in a string when it's not followed or preceded alphanumeric chars

I've got the test string:

$string="or(or apple and orange) or banana"

I want to replace any instance of
in the string when it's not part of another word, e.g.
and just make it uppercase and ensure there's spaces on either side of it.

So the above string should become:
OR ( OR apple and orange) OR banana

I'm not terribly good at regex, and I've tried:

$string = preg_replace('([^a-zA-Z]or[^a-zA-Z])', ' OR ', $string);

Which gives me:
or OR apple and orange) OR banana

And that is quite far off. What would be correct regex to achive the desired output?:

Answer Source

Use word boundary(\b)

$string = preg_replace("/\bor\b/", 'OR', $string);
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