I need a small algorithm in ruby to find x and y.
slope = Math.tan(ang) x = (dInf - dSup)/(2 * slope) y = x*slope + (dSub/2)
Y will be either positive or negative depending on which corner you want.
The reasoning for this is that the equation for the top slanted line is: Y = Sin(ang) * X + (dSup/2)
So the question becomes "at what X do we get a Y = dInf/2"
Substituting Y: Sin(ang) * X + (dSup/2) = dInf/2
Rearranging: X = (dInf - dSup) / 2 Sin(ang)