Danny Garcia - 2 years ago 176

Python Question

I'm trying to iterate through a list (range entered by user), at first assume that all numbers are prime (P), and have the program iterate through the list. When the element in the list is P, I want to iterate through all multiples within the range and change them to N. When the element is N, I want the program to move onto the next number (I set 0 and 1 to not prime, as they are exceptions). I'm running into an issue with indexing however, I get the error:

`list1[number1] = 'N'`

IndexError: list assignment index out of range

When I run the program I have. Here is the code:

`# input`

n = int(input("Enter a positive integer greater than or equal to 10: "))

while n < 10:

print ("Invalid! Try again")

int(input("Enter a positive integer greater than or equal to 10: "))

# create list

new_n = n + 1

list1 = ['P'] * new_n

# set non prime

list1[0] = 'N'

list1[1] = 'N'

# set up loop

counter = 0

for x in list1:

counter1 = 2

if list1[counter] == 'P':

for y in list1:

number1 = counter * counter1

list1[number1] = 'N'

counter1 += 1

counter += 1

else:

counter += 1

Any help would be appreciated! Thanks.

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Answer Source

In your loops, you're setting only squared value as non prime because you iterate `counter`

in `counter1`

's loop. Then, you have to check if `number1`

is lesser than the size of `list1`

.

This code works:

```
# set up loop
counter = 0
for x in list1:
counter1 = 2
if list1[counter] == 'P':
for y in list1:
number1 = counter * counter1
if number1 < len(list1):
list1[number1] = 'N'
counter1 += 1
else:
counter += 1
```

Besides, you should simplify your code using `enumerate`

and `range`

:

```
# set up loop
for i, val in enumerate(list1):
if val == 'P':
for j in range(2, len(list1)):
if i*j < len(list1):
list1[i*j] = 'N'
else:
break
```

Here's the result for n = 12:

```
Enter a positive integer greater than or equal to 10: 12
['N', 'N', 'P', 'P', 'N', 'P', 'N', 'P', 'N', 'N', 'N', 'P', 'N']
```

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