Geri - 1 year ago 106

Python Question

I have an array like

`a = np.array[ 4, 9, 3, 1, 6, 4, 7, 4, 2]`

and a boolean array (so that's a mask) of same size like

`boo = np.array[ True, True, False, False, True, True, True, False, True]`

(

`boo`

`False`

Now I want to split

`a`

- a new sub array contains only values with in
`True`

`boo`

- a new sub array begins always after a and ends before a
`False`

.`False`

So a result would be`[[4, 9], [6, 4, 7], [2]]`

I know that I can use

`np.split`

In this case it would be

`b = np.split(a, [2, 4, 7, 8]`

`b`

`boo`

`True`

So my problem is: How do I get the array

`[2, 4, 7, 8]`

(Looping with python is not an option, because it's too slow.)

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Answer Source

Maybe this is fast enough:

```
d = np.nonzero(boo != np.roll(boo, 1))[0]
if d[0] == 0:
d = d[1:]
b = np.split(a, d)
b = b[0::2] if boo[0] else b[1::2]
```

Found a simpler and faster way:

```
indices = np.nonzero(boo[1:] != boo[:-1])[0] + 1
b = np.split(a, indices)
b = b[0::2] if boo[0] else b[1::2]
```

Comparing slices is at least twice as fast as `np.roll()`

plus the if statement.

Also, `np.flatnonzero(...)`

would look nicer than `np.nonzero(...)[0]`

but be slightly slower.

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