user3821012 - 1 year ago 140

Python Question

I want to detect consecutive spans of 1's in a numpy array. Indeed, I want to first identify whether the element in an array is in a span of a least three 1's. For example, we have the following array a:

`import numpy as np`

a = np.array([1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0])

Then the following 1's in bold are the elements satisfy the requirement.

[

Next, if two spans of 1's are separated by at most two 0's, then the two spans make up a longer span. So the above array is charaterized as

[

In other words, for the original array as input, I want the output as follows:

`[True, True, True, True, True, True, True, False, False, False, False, False, True, True, True, True, True, True, True, True, True, True, False]`

I have been thinking of an algorithm to implement this function, but all the one I come up with seems to complicated. So I would love to know better ways to implement this -- it would be greatly appreciated if someone can help me out.

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

Instead of solving the conventional way of looping and maintaining count we can convert all 0's and 1's to a single string and replace a regex match with another char say `2`

. Once that is done we split out the string again and check for `bool()`

over each char.

```
>>> import re
>>> lst=[1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]
>>> list(map(bool, map(int, list(re.sub(r'1{3,}0{1,2}1{3,}', lambda x:'2'*len(x.group()), ''.join(map(str, lst)))))))
[True, True, True, True, True, True, True, False, True, True, False, False, True, True, True, True, True, True, True, True, True, True, False]
>>>
```

All the magic happens over here:

```
re.sub(r'1{3,}0{1,2}1{3,}', lambda x:'2'*len(x.group()), ''.join(map(str, lst)))
```

where it searches for a contiguous occurrence of 3 or more 1's followed by at most 2 0's i.e 1 or 2 0's followed by 3 or more 1's and replaces the whole matched string a same length string of 2's (used 2 because `bool(2)`

is `True`

). Also you can use `tolist()`

method in `NumPy`

to get a list out of NumPy array like this: `np.array([1,2, 3, 4, 5, 6]).tolist()`

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**