[Disclaimer: there may be more pythonic ways of doing what I want to do, but I want to know how python's scoping works here]
I'm trying to find a way to make a decorator that does something like injecting a name into the scope of another function (such that the name does not leak outside the decorator's scope). For example, if I have a function that says to print a variable named
c = 'Message'
def inner_dec(*args, **kwargs):
var = value
res = f(*args, **kwargs)
NameError: global name 'var' is not defined
<ipython-input-25-34b84bee70dc> in inner_dec(*args, **kwargs)
8 def inner_dec(*args, **kwargs):
9 var = value
---> 10 res = f(*args, **kwargs)
11 return res
12 return inner_dec
You can't. Scoped names (closures) are determined at compile time, you cannot add more at runtime.
The best you can hope to achieve is to add global names, using the function's own global namespace:
def decorator_factory(value): def msg_decorator(f): def inner_dec(*args, **kwargs): g = f.func_globals sentinel = object() oldvalue = g.get('var', sentinel) g['var'] = value try: res = f(*args, **kwargs) finally: if oldvalue is sentinel: del g['var'] else: g['var'] = oldvalue return res return inner_dec return msg_decorator
f.func_globals is the global namespace for the wrapped function, so this works even if the decorator lives in a different module. If
var was defined as a global already, it is replaced with the new value, and after calling the function, the globals are restored.
This works because any name in a function that is not assigned to, and is not found in a surrounding scope, is marked as a global instead.
>>> c = 'Message' >>> @decorator_factory(c) ... def msg_printer(): ... print var ... >>> msg_printer() Message >>> 'var' in globals() False
But instead of decorating, I could just as well have defined
var in the global scope directly.
Note that altering the globals is not thread safe, and any transient calls to other functions in the same module will also still see this same global.